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Q.

A one liter glass flask contains some mercury. It is found that at different temperatures the volume of air inside the flak remains the same. What is the volume of mercury in this flask if coefficient of linear expansion of glass is 9 x 10^–6/°C while of volume expansion of mercury is 1.8 x 10^–4/°C

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a

50 cc

b

100 cc

c

150 cc

d

200 cc

answer is C.

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Detailed Solution

It is given that the volume of air in the flask remains the same. This means that the expansion in volume of the vessel is exactly equal to the volume expansion of mercury.
$i.e.,\,\,\Delta {V_g} = \Delta {V_L}\,or\,{V_g}{\gamma _g}\Delta \theta = {V_L}{\gamma _L}\Delta \theta$
$\therefore {V_L} = \frac{{{V_g}{\gamma _g}}}{{{\gamma _L}}} = \frac{{1000 \times (3 \times 9 \times {{10}^{ - 6}})}}{{1.8 \times {{10}^{ - 4}}}} = 150\,cc$

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