A one litre glass flask contains some mercury. It is found that at different temperatures, the volume of air inside the flask remains the same. Volume of mercury in the flask is :
(Given $α_{glass} = 9 \times 10^{- 6} /^{\circ} C; γ_{Hg} = 1 .8 \times 10^{- 4} /^{\circ} C$ )

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100 cm³

120 cm³

150 cm³

200 cm³

answer is C.

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Detailed Solution

$∵ V_{g} - V_{Hg} = constant$

$∴ ∆ V_{g} = ∆ V_{Hg} \Rightarrow V_{g} (3 α_{g}) ∆ T = (V_{Hg}) (γ_{Hg}) ∆ T \Rightarrow V_{Hg} = (\frac{3 α_{g}}{γ_{Hg}}) V_{g} = 150 {cm}^{3}$

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