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A P-N junction diode can withstand currents up to 10 mA. Under forward bias, the diode has a potential drop of 0.5 V across it which is assumed to be independent of current. The maximum voltage of the battery used to forward bias the diode when a resistance $200 Ω$ of is connected in series with it is

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$2.5 V$

$2.6 V$

$2.7 V$

$2.8 V$

answer is A.

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Detailed Solution

$i = \frac{E - V_{b}}{R}$

$E = 0.01 \times (200 + \frac{0.5}{0.01}) = 2.5 V$

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