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Q.

A pair of dice is thrown once. Find the probability of getting doublet of prime numbers.


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a

3 12  

b

1 11  

c

5 12  

d

1 12   

answer is D.

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Detailed Solution

Given, a pair of dice is thrown once.
The probability of an event occurring is calculated by dividing the number of favourable outcomes by the total number of outcomes; that is,
 Probability of an cvent =  Number of favourable outcomes   Total number of outcomes   
Find the total number of possible outcomes.
Throwing the two dice has two possible outcomes-6 and 6.
As a result, the total number of possible outcomes is 6×6=36   .
Find the positive outcomes that the doublets are prime numbers.
The positive outcomes of doublets being prime numbers are (2,2), (3,3) and (5,5).
So, the number of favourable outcomes that the doublets are prime numbers is three.
Find the required probability by dividing the number of favourable outcomes by the total number of possible outcomes which is, 3 and 36 in this case.
 Probability  =  Number of favourable outcomes   Total number of possible outcomes  = 3 36 = 1 12    The probability of getting doublet of prime numbers is 1 12  .
Hence the correct answer is option 4.
 
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