Q.

A pair of fair dice is rolled. If sum of the numbers obtained is less than 5 then a letter is chosen at random from the letters of the word DIVIDE. If the sum is more than 9 then a letter is chosen at random from the letters of the word GARDEN. Otherwise a letter is chosen at random from the letters of the word INDIAN. If probability of getting a prime score when the selected letter is a vowel is ‘p’, then the integral part of 17p is 

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answer is 7.

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Detailed Solution

Let E1:sum5,E2:6sum9 and E3:sum9 
PE1=1+2+336=16,PE3=16PE2=2436=46 
Let E be the event of choosing a vowel. Using Baye’s theorem 
PE1E=16×3616×36+46×36+16×26=317 
Similarly  PE2/E=12/17 and PE3/E=2/17 
Required probability 
P=317×1+26+1217×4+624+217×2617P=32+5+23=43617p=7   

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