A pair of parallel conducting rails lies at right angle to a uniform magnetic field of 2.0 T as shown in the figure. Two resistors $10 Ω and 5 Ω$ are to slide without friction along the rail. The distance between the conducting rails is 0.1 m. Then

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Induced current $= \frac{1}{150} A$ directed anti-clockwise if 5A resistor is pulled to the left at $0.5 {ms}^{- 1}$ and $10 Ω$ resistor is held at rest

Induced current $= \frac{1}{300} A$ e directed anti-clockwise if $10 Ω$ resistor is pulled to the right with speed $0.5 {ms}^{- 1}$ and $5 Ω$ resistor is held fixed

Induced current $= \frac{1}{150} A$ directed clockwise if $10 Ω$ resistor is pulled to the right with speed $0.5 {ms}^{- 1}$ and $5 Ω$ resistor is held fixed

Induced current $= \frac{1}{300} A$ directed clockwise if $5 Ω$ resistor is pulled to the left a $0.5 {ms}^{- 1}$ and $10 Ω$ resistor is held at rest

answer is D.

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Detailed Solution

When $5 Ω$ resistor is pulled left at 0.5 m/s, induced emf in the said resistor $= e = vBl = 0 .5 \times 2 \times 0 .1 = 0 .1 V$ Resistor $10 Ω$ is at rest so induced emf in it (e = vBl) is zero.