A parachutist after bailing out falls $50 m$ without friction. When parachute opens, it decelerates at $2 m / s^{2}$ . He reaches the ground with a speed of $3 m / s$ . At what height, did he bail out :

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$293 m$

$91 m$

$182 m$

$111 m$

answer is B.

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Detailed Solution

Velocity of a parachute after falling 50m

$u = \sqrt{2 g x 50} = 10 \sqrt{g} m / s 3^{2} = u^{2} - 2 x 2 x h 3^{2} = 100 g - 4 h h = 243 m T h e h e i g h t a t w h i c h p a r a c h u t e b a i l s o u t, 243 + 50 = 293 m$

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