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Q.

A parachutist drops freely from an airplane for 8s before the parachute opens out.  Then he descends with a net retardation of 2ms2 reaching the ground with a velocity of 6ms1.  The height from which he bails out of the aeroplane is g=10ms2

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a

1929 m         

 

b

1911 m 

c

2195 m

d

2000 m

answer is B.

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Detailed Solution

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v=u+atv=0+10×8V=80m/ss=ut+12at2h1=0+12×10×82h1=320mVf2=Vi2+2asS=Vf2Vi22ah2=628022×(2)h2=1591m Total heighth =h1+h2=1911m

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