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Q.

A parallel beam of light is incident on a fixed surface PQ at an angle 'θ' with the vertical as shown in the figure. The intensity of light is I and area of surface PQ is A. In List-I nature of reflection are given and in List-II force and generated radiation pressure are given. Then match List-I with suitable option List-II. (Given that I = 500 W/m2 , A=1.5m2,θ=370 )

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LIST-ILIST-II
P)If all the incident energy is absorbed by surface PQ then force on the surface and radiation pressure generated are respectively.1)3.2×106N,2.13×106N/m2
Q)If all the incident energy is reflected by surface PQ then force on the surface and radiation pressure generated are respectively.2)2.24×106N,1.38×106N/m2
R)If 30% incident energy is reflected by the surface then force on the surface and pressure generated are respectively. (Rest absorbed)3)2.74×106N,1.81×106N/m2
S)If 70% incident energy is reflected back then force on the surface and radiation pressure are respectively. (Rest absorbed)4)2×106N,1.06×106N/m2
  5)4.2×106N,3.13×106N/m2

 

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a

P3;Q5;R4;S2

b

P4;Q1;R2;S3

c

P4;Q1;R3;S2

d

P3;Q2;R1;S4

answer is D.

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Detailed Solution

Intensity is given by  I=N(hCλ)(Acosθ)Δt,where
N total number of photons and  λ
wavelength of photons

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 (A)  Fx=ΔPxΔt=IAcosθ.sinθC Fy=ΔPyΔt=IAcosθcosθC pr=FyA=Icos2θC (B)  Fx=0 Fy=2IAcos2θC pr=2IAcos2θC

(C) and (D)
 Fx=IAcos2θC(1r) Fy=IAcos2θC(1+r) prIcos2θC(1+r)

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