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A parallel beam of light of wavelength 500 nm falls on a narrow slit and the resulting diffraction pattern is observed on a screen 1 m away. It is observed that the first minimum is at a distance of 2.5 mm from the centre of the screen . The width of the slit is

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0.1 mm

1 mm

0.5 mm

0.2 mm

answer is C.

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Detailed Solution

$y_{n^{th}} = \frac{nλD}{d}$

n=1,

$d = \frac{500 \times 10^{- 9} \times 10}{2.5 \times 10^{- 3}} m = 0.2 mm$

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