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A parallel connection is made between a resistor X and an $8 ohm$ resistor. If the combination's final resistance is $4.8 ohms$ , then the resistor X's value is [[1]] ohms.

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Detailed Solution

The combination's final resistance of the given resistances that are connected in parallel is:

R_{p} = \frac{(8) (X)}{8 + X}

\Rightarrow

4.8 = \frac{(8) (X)}{8 + X}

\Rightarrow

38.4 + 4.8 X = 8 X

\Rightarrow

X = 12 ohms

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