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A parallel plate air capacitor has a capacitance of 100μF. The plates are at a distance d apart. If a slab of thickness
$t(t leq d)$
and dielectric constant 5 is introduced between the parallel plates, then the capacitance will be

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$large 50 mu F$

$large 100 mu F$

$large 200 mu F$

$large 500mu F$

answer is C.

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Detailed Solution

Capacitance will increase but not 5 times (because dielectric is not filled completely). Hence new capacitance may be 200 μF.

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