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A parallel plate capacitor consists of two circular plates each of radius 2 cm, separated by a distance of 0.1 mm. If voltage across the plates is varying at the rate of $5 \times 10^{13} V / s$ then the value of displacement current is

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5.50 A

$2.28 \times 10^{4} A$

$5.56 \times 10^{2} A$

$5.56 \times 10^{3} A$

answer is C.

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Detailed Solution

$I_{d} = ε_{0} A \frac{dE}{dt} = ε_{0} \frac{A}{d} \frac{dV}{dt}$

$= \frac{8 .86 \times 10^{- 12} \times 3 .14 \times {(2 \times 10^{- 2})}^{2}}{0 .1 \times 10^{- 3}} \times 5 \times 10^{13} = 5.56 \times 10^{3} A$

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