A parallel plate capacitor consists of two circular plates of radius 0.05 m. If electric field between the plates is changed as dEdt=1010Vm-s ,then the displacement current between the plates is x mA. What is x ? (Round off to the nearest integer)

Id=ε0AdEdt=8.85×10−12×π(.05)2×1010≃0.7mA

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A parallel plate capacitor consists of two circular plates of radius 0.05 m. If electric field between the plates is changed as $\frac{dE}{dt} = 10^{10} \frac{V}{m - s}$ ,then the displacement current between the plates is x mA. What is x ? (Round off to the nearest integer)

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$\begin{array}{l} I_{d} = ε_{0} A \frac{dE}{dt} \\ = 8.85 \times 10^{- 12} \times π (. 05)^{2} \times 10^{10} ≃ 0.7 mA \end{array}$

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