A parallel plate capacitor has two layers of dielectrics as shown in figure. This capacitor is connected across a battery, then the ratio of potential difference across the dielectric layers is

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$\frac{4}{3}$

$\frac{1}{2}$

$\frac{1}{3}$

$\frac{3}{2}$

answer is C.

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Detailed Solution

The Capacitance of the two layers are given by $C_{1} = \frac{2 ε_{0} A}{d}; C_{2} = \frac{6 ε_{0} A}{2 d}$
As q is same on each condenser, therefore $\frac{V_{1}}{V_{2}} = \frac{C_{2}}{C_{1}} = \frac{3}{2}$

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