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Q.

A parallel plate capacitor is charged by a battery which is then disconnected. A dielectric slab is then
inserted to fill the space between the plates. Match the changes that could occur with Column II and
choose the correct code.

Column IColumn II
A. Charge on the capacitor plates(p) Decrease by a factor of K
B. Intensity of electric field(g) Increase by a factor of K
C. Energy stored(r) Remains same
D. Capacitance(s) None

Codes

A  B  C  D

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a

p s q r

b

r p p q

c

r q s p

d

p r q s

answer is A.

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Detailed Solution

A dielectric slab is when inserted to fill the space between the plates and battery is removed, then

QuantityBattery is removed
CapacityC' = KC
ChargeQ' = Q
PotentialV' = V/K
Electric fieldE' = E/K
EnergyU' = U/K
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A parallel plate capacitor is charged by a battery which is then disconnected. A dielectric slab is theninserted to fill the space between the plates. Match the changes that could occur with Column II andchoose the correct code.Column IColumn IIA. Charge on the capacitor plates(p) Decrease by a factor of KB. Intensity of electric field(g) Increase by a factor of KC. Energy stored(r) Remains sameD. Capacitance(s) NoneCodesA  B  C  D