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A parallel plate capacitor is charged from a cell and then isolated from it. If F be the force of attraction between the plates of the capacitor, E be the electric field in the region between the plates, U be the electrostatic energy stored in the capacitor and $ΔV$ be the potential difference between the plates of the capacitor, then on increasing the separation between the plates we observe that

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U increases

F decrease

$Δ V$ Decreases

E remains constant

answer is A, D.

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Detailed Solution

When isolated from the battery after charging the charge on the capacitor remains constant.

When the separation is increased, capacitance decreases.

Hence potential difference increases and potential energy stored also increases.

Field and force between the plates stays unaltered.

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