A parallel plate capacitor is made of two circular plates separated by a distance of 5 mm with a dielectric of dielectric constant 2.2 between them. When the electric field in the dielectric is $3 \times 10^{4} V / m$ , the charge density of the positive plate will be close to

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$3 \times 10^{- 7} C / m^{2}$

$6 \times 10^{4} C / m^{2}$

$6 \times 10^{- 7} C / m^{2}$

$3 \times 10^{4} C / m^{2}$

answer is A.

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Detailed Solution

Electric field inside dielectric, $\frac{σ}{K ε_{o}} = 3 \times 10^{4}$

$\begin{array}{l} \Rightarrow σ = 2.2 \times 8.58 \times 10^{- 12} \times 3 \times 10^{4} \\ = 6.6 \times 8.85 \times 10^{- 8} \\ = 5.841 \times 10^{- 7} = 6 \times 10^{- 7} C / m^{2} \end{array}$

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