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A parallel plate capacitor is made of two circular plates separated by a distance of 5 mm and with a dielectric of dielectric constant 2.2 between them. When the electric field in the dielectric is 3 x 10⁴ V/m, the charge density of the positive plate will be close to:

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$6 \times 10^{4} C / m^{2}$

$6 \times 10^{- 7} C / m^{2}$

$3 \times 10^{- 7} C / m^{2}$

$3 \times 10^{4} C / m^{2}$

answer is B.

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Detailed Solution

$E = \frac{σ}{ε} = \frac{σ}{{Kε}_{0}} = 3 \times 10^{4} V / m ∴ σ = {Kε}_{0} \times 3 \times 10^{4} = 2 .2 \times 8 .854 \times 10^{- 12} \times 3 \times 10^{4} = 6 \times 10^{- 1} {Cm}^{- 2}$

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