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Q.

A parallel plate capacitor is of area  6cm2 and a separation 3mm. The gap is filled with three dielectric materials of equal thickness (see figure) with dielectric constants K1=10,  K2=12 and K3=14. The dielectric constant of a material which give same capacitance when fully inserted in above capacitor, would be

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a

4

b

36

c

12

d

14

answer is C.

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Detailed Solution

In the given arrangement capacitor can be viewed as three-different capacitors connected in parallel as shown below

Question Image

So, equivalent capacity of the system is

Ceq=C1+C2+C3Kε0Ad=K1ε0A/3d+K2ε0A/3d+K3ε0A/3d

K=K13+K23+K33

Here K1=10K2=12 and  K3=14
So, K=10+12+143K=12

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