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Q.

A parallel plate capacitor of capacitance 2 F is charged to a potential V. The energy stored in the capacitor is E1. The capacitor is now connected to another uncharged identical capacitor in a parallel combination. The energy stored in the combination is E2. The ratio E2/E1 is : 

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a

2 : 1

b

2 : 3

c

1 : 4

d

1 : 2

answer is D.

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Detailed Solution

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E1=12CV2
E2=2×12C(V2)2=12CV22=E12
∴ E2E1=12

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