A parallel plate capacitor of capacitance 90 pF is connected to a battery of emf 20 V. if a dielectric material of dielectric constant K = 5 / 3 is inserted between the plates, the magnitude of the induced charge will be ______

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2.4 nC

1.2 nC

0.9 nC

0.3 nC

answer is B.

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Detailed Solution

The charge in capacitor after placing the dielectric
$Q_{1} = C_{1} V$
The induced charge on dielectric surface
$\begin{array}{l} Q_{induced} = Q_{1} (1 - \frac{1}{K}) \\ Q_{induced} = 3 (1 - \frac{1}{5 / 3}) = 3 \times \frac{2}{5} = \frac{6}{5} = 1 .2 nC \end{array}$

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