A parallel plate capacitor of capacitance 90 pF is connected to a battery of emf 20V. If dielectric material of dielectric constant K=53 is inserted between the plates the magnitude of induced charge on the dielectric slab is___pC.

Induced charge on Dielectric Qi=(K−1)CV =(53−1)×90×10−12×20 =40×30×10−12CQi=1200pC

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A parallel plate capacitor of capacitance 90 pF is connected to a battery of emf 20V. If dielectric material of dielectric constant $K = \frac{5}{3}$ is inserted between the plates the magnitude of induced charge on the dielectric slab is___pC.

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Detailed Solution

Induced charge on Dielectric
$\begin{array}{l} Q_{i} = (K - 1) CV \\ = (\frac{5}{3} - 1) \times 90 \times 10^{- 12} \times 20 \\ = 40 \times 30 \times 10^{- 12} C \\ Q_{i} = 1200 pC \end{array}$

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