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A parallel plate capacitor of capacitance C (without dielectrics) is filled by dielectric slabs as shown in figure. Then the new capacitance of the capacitor is:

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3.9 C

4 C

3 C

2.4 C

answer is A.

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Detailed Solution

The equivalent capacitance Ceq = $\frac{2 C \times 6 C}{2 C + 6 C} + \frac{6 C \times 4 C}{6 C + 4 C} = 3.9 C$

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