Q.

A parallel plate capacitor with air as dielectric is charged to a potential ‘V’ using a battery.  Removing the battery, the charged capacitor is then connected across an identical uncharged parallel plate capacitor filled with wax of dielectric constant ‘k’ . The common potential of both the capacitor is 

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a

V volts 

b

kV volts 

c

Vk+1 volts 

d

(k+1) V volts

answer is D.

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Detailed Solution

Capacitance with air as dielectric C=ε0Ad
For identical capacitor capacitance with wax as dielectric C=εAd
C=KC, where K=εεo
When C and  are conncected in parallel Charge is distributed and the potential Difference is equal for the two capacitors Resultant capacitance CR=C+Cand the total charge Q = CV
Common  potential V=dQ
CR=d CV C+C
V=CVC+KC=VK+1
 

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