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A parallel plate condenser has initially air medium between the plates. If a slab of dielectric constant 5 having thickness half the distance of separation between the plates is introduced, the percentage increase in its capacity is

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33.3%

66.7%

50%

75%

answer is B.

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Detailed Solution

$C_{0} = \frac{ε_{0} A}{d}; C = \frac{\in_{0} A}{d - t (1 - 1 / k)}$

$△ C % = \frac{C - C_{0}}{C_{0}} \times 100 %$

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