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A parallel plate condenser has plates of area 200 cm² and separation 0.05 cm. The space between plates have been filled with a dielectric having K=8 and then charged to 300 volts. The stored energy

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a

12.4 × 10^–5 J

b

1.6 × 64 × 10^–5 J

c

1.6 × 10^–5 J

d

2 × 10^–6 J

answer is C.

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Detailed Solution

$\begin{array}{l} C = {KC}_{0} = K \frac{{Aε}_{0}}{d} = 8 \times \frac{8 .85 \times 10^{- 12} \times 200 \times 10^{- 4}}{5 \times 10^{- 4}} \\ U = \frac{1}{2} {CV}^{2} = \frac{1}{2} \times 320 \times 8 .85 \times 10^{- 12} \times {(3 \times 10^{2})}^{2} \\ = 12 .4 \times 10^{- 5} J \end{array}$

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