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Q.

A parallel plate condenser has plates of area 200 cm² and separation 0.05 cm. The space between plates have been filled with a dielectric having $K = 8$ and then charged to 300 volts. Then, the energy stored is

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a

$2 \times 10^{- 6} J$

b

$1 .65 \times 10^{- 5} J$

c

$12.4 \times 10^{- 5} J$

d

$1 .6 \times 64 \times 10^{- 5} J$

answer is C.

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Detailed Solution

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$U = \frac{1}{2} (\frac{{KAε}_{0}}{d}) V^{2} ≃ 12.4 \times 10^{- 5} J$

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