A parallel plate condenser with air between the plates possesses the capacity of 10-12 F. Now, the plates are removed apart, so that the separation is twice the original value. The space between theplates is filled with a material of dielectric constant 4.0. Then new value of the capacity is (in farad)

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A parallel plate condenser with air between the plates possesses the capacity of $10^{- 12} F$ . Now, the plates are removed apart, so that the separation is twice the original value. The space between the
plates is filled with a material of dielectric constant 4.0. Then new value of the capacity is (in farad)

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$3 \times 10^{- 12}$

$0.5 \times 10^{- 12}$

$4 \times 10^{- 12}$

$2 \times 10^{- 12}$

answer is C.

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