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A paramagnetic sample shows a net magnetization of 0.8 A/m, when placed in an external magnetic field of strength 0.8T at a temperature 5K. When the same sample is placed in an external magnetic field of 0.4 T at a temperature of 20K, the magnetization is

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$0.8 {Am}^{- 1}$

$0.4 {Am}^{- 1}$

$0.2 {Am}^{- 1}$

$0.1 {Am}^{- 1}$

answer is D.

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Detailed Solution

$ψ = \frac{C}{T}$

$\frac{I}{H} = \frac{C}{T}$

$\frac{I_{1}}{I_{2}} \times \frac{H_{2}}{H_{1}} = \frac{T_{2}}{T_{1}}$

$\Rightarrow \frac{I_{1} T_{1}}{B_{1}} = \frac{I_{2} T_{2}}{B_{2}} ∴ \frac{0.8 \times 5}{0.8} = \frac{M_{2} \times 20}{0.4} \Rightarrow M_{2} = 0.1 {Am}^{- 1}$

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