Q.

A paramagnetic substance in the form of a cube with sides 1 cm has a magnetic dipole moment of 20×106J/T. When a magnetic intensity of 60×103A/m is applied. Its magnetic susceptibility is

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a

3.3×104

b

3.3×102

c

4.3×102

d

2.3×102

answer is C.

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Detailed Solution

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χ=IH  and  I=MV=20×106106=20N/m2

χ=2060×103=0.33×103=3.3×104

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