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Q.

A park in the shape of a quadrilateral ABCD   has AB = 9 m, BC = 12 m, CD = 5 m, AD = 8 m and c= 90 °  . The area of the park is ____ m 2  . [Given: 35 =5.9  ]


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Detailed Solution

A park in the shape of a quadrilateral ABCD   has AB = 9 m, BC = 12 m, CD = 5 m, AD = 8 m and C= 90 °  . The area of the park is 65.4 m 2  .
Given a quadrilateral ABCD   with AB = 9 m, BC = 12 m, CD = 5 m, AD = 8 m and C= 90 °  .
Question ImageAs BCD is a right-angled triangle, using Pythagoras theorem,
hypotenuse 2 = base 2 + perpendicular 2 hypotenuse= base 2 + perpendicular 2   BD = B C 2 +C D 2 BD = 12 2 + 5 2 BD = 169 BD = 13m   Now area of Δ  BCD is,
Area of triangle=  1 2 ×base×height   Area of ΔBCD= 1 2 ×BC×CD Area of ΔBCD= 1 2 ×12×5 Area of ΔBCD=30 m 2  
The value of semi perimeter (s) for Δ  ABD is,
s = a+b+c 2 s = 9+8+13 2 s = 15m  
Now, using Heron’s formula in triangle ABD
Area of ΔABD= s sa sb sc Area of ΔABD= 15 159 158 1513 Area of ΔABD=3×2 35 Area of ΔABD=35.4 m 2   Overall area of quadrilateral is,
Area of ABCD= 30 + 35.4 Area of ABCD= 65.4  m 2  
The area of the park is 65.4 m 2  .
 
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