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A particle starts with an initial velocity of ${10ms}^{- 1}$ and moves with a uniform acceleration. It attains a velocity of ${30ms}^{- 1}$ in $5 s$ . The time taken by the particle from here onwards to acquire a velocity of ${60ms}^{- 1}$ is

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5 . 5s

4 . 5s

7 . 5s

6 . 5s

answer is D.

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Detailed Solution

u = 10 m / s v = 30 m / s t = 5s

$a = \frac{v - u}{t} = \frac{30 - 10}{5} = \frac{20^{4}}{5_{1}} = 4 m s^{- 2}$

$a = 4 m s^{- 2}$

$a = \frac{v - u}{t} (o r) t = \frac{v - u}{a}$

$u = 30 m / s, v = 60 m / s, t = ? a = {4ms}^{- 2}$

$t = \frac{60 - 30}{4} = \frac{30^{7.5}}{4_{1}}$

$t = 7.5 s$

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