A particle 'A' is moving along a circle with uniform speed and another particle B is in circular motion with variable speed. If W_A and W_B are the work done in their circular motions then :

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W_A = W_B = 0

$W_{A} = 0, W_{B} \neq 0$

$W_{A} \neq 0, W_{B} = 0$

$W_{A} = W_{B} \neq 0$

answer is B.

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Detailed Solution

Kinetic Energy of particle A is constant, hence no work is done on it where as kinetic energy of particle B is changing hence work done for particle B will be non zero.

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