A particle A is moving with velocity (3i^+4j^) m/s and particle B is moving with velocity (−3i^−4j^) m/s . The magnitude of velocity of B w.r.t A is

V¯BA=V¯B−V¯A=(−3i^−4j^)−(3i^+4j^)V¯BA=−6i^−8i^⇒VBA=62+82=10m/s

A particle A is moving with velocity (3i^+4j^) m/s and particle B is moving with velocity (−3i^−4j^) m/s . The magnitude of velocity of B w.r.t A is

V¯BA=V¯B−V¯A=(−3i^−4j^)−(3i^+4j^)V¯BA=−6i^−8i^⇒VBA=62+82=10m/s

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A particle A is moving with velocity $(3 \hat{i} + 4 \hat{j}) m / s$ and particle B is moving with velocity $(- 3 \hat{i} - 4 \hat{j}) m / s$ . The magnitude of velocity of B w.r.t A is

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6 m/s

8 m/s

10 m/s

5 m/s

answer is C.

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$\begin{array}{l} {\bar{V}}_{BA} = {\bar{V}}_{B} - {\bar{V}}_{A} \\ = (- 3 \hat{i} - 4 \hat{j}) - (3 \hat{i} + 4 \hat{j}) \\ {\bar{V}}_{BA} = - 6 \hat{i} - 8 \hat{i} \Rightarrow |V_{BA}| = \sqrt{6^{2} + 8^{2}} \\ = 10 m / s \end{array}$

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A particle A is moving with velocity (3i^+4j^) m/s and particle B is moving with velocity (−3i^−4j^) m/s . The magnitude of velocity of B w.r.t A is

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A particle A is moving with velocity $(3 \hat{i} + 4 \hat{j}) m / s$ and particle B is moving with velocity $(- 3 \hat{i} - 4 \hat{j}) m / s$ . The magnitude of velocity of B w.r.t A is