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A particle at rest starts moving along a horizontal straight line with a uniform acceleration $a_{0}$ .The distance travelled in the $4^{th}$ second of its motion is

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${3a}_{0}$

$a_{0} /2$

${5a}_{0}$

${7a}_{0} /2$

answer is C.

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Detailed Solution

$s_{n} = u + \frac{a}{2} (2 n - 1)$

$= 0 + \frac{a}{2} (8 - 1)$

$= \frac{7 a}{2}$

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