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A particle does uniform circular motion in a horizontal plane. The centripetal force acting on the particle is 10 N. It's kinetic energy is 1 joule. The radius of the circular path is

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0.02 m

2 m

0.1 m

0.2 m

answer is B.

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Detailed Solution

$\frac{m v^{2}}{r} = 10 a n d \frac{1}{2} m v^{2} = 1 m v^{2} = 10 r \frac{1}{2} 10 r = 1 r = \frac{2}{10} m = 0.2 m$

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