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Q.

A particle execute in S.H.M whose displacement equation is Y = 5 sin (10t–π /3). The minimum time after which the K.E of the particle will be maximum is

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a

π30sec

b

π60sec

c

π90sec

d

π120sec

answer is A.

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Detailed Solution

When y = 0;
velocity and KE are maximum
y=5sin⁡(10t−π/3)=0⇒10t−π/3=0;t=π/30

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