A particle executes SHM such that the maximum velocity during the oscillation is numerically equal to half the maximum acceleration, what is the time period ?

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Detailed Solution

$\begin{array}{l} V_{max} = \frac{1}{2} (a_{max}) \\ Aω = \frac{1}{2} ({Aω}^{2}) \\ \Rightarrow ω = 2 \\ T = \frac{2 π}{ω} = \frac{2 π}{2} = π seconds \end{array}$

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