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Q.

A particle executes simple harmonic motion according to the displacement equation y = 10 cos(2πt+π6)cm;, where t is in seconds. The velocity of the particle at t = 16 seconds will be:

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a

-0.628 ms-1

b

0.628 ms-1

c

-6.28 ms-1

d

6.28 ms-1

answer is .

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Detailed Solution

Velocity v = dydt = ddt[10 cos(2πt+π6)]

                   = -20π sin(2πt+π6) cms-1

v(16) = -20(3.14)sin(π3+π6)cms-1

    = 62.8 cm s-1(numerically)        [Using sin π2 = 1]   

     = 0.628 ms-1

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A particle executes simple harmonic motion according to the displacement equation y = 10 cos(2πt+π6)cm;, where t is in seconds. The velocity of the particle at t = 16 seconds will be: