Q.

A particle executes simple harmonic motion of period T and amplitude l along a rod AB of  length 2l. The rod AB itself executes simple harmonic motion of the same period and amplitude in a direction perpendicular to its length. Initially, both the particle and the rod are in their mean positions. The path traced out by the particle will be

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a

a circle of radius l   

b

an ellipse

c

 a straight line inclined at \large \frac{\pi }{4} to the rod

d

a figure of eight

answer is B.

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Detailed Solution

\large x\, = \,A\sin \omega t;\,y\,\, = \,\,A\sin \omega t\,;\,x = \,y

Equation of  Straight line , with slope

\large m\, = \,\tan \theta \, = \,1\, \Rightarrow \,\theta \, = \,{45^o}\, = \,\frac{\pi }{4}

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