Q.

A particle executes simple harmonic motion represented by displacement function as x(t)=Asin(ωt+ϕ). If the position and velocity of the particle at t=0s are 2 cm and 2ω  cms1  respectively, then its amplitude is x2cm where the value of x is ______.

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answer is 2.

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Detailed Solution

Given:

x(t)=Asin(ωt+ϕ) v(t)=fdxdt v(t)=Aωcos(ωt+ϕ) 2=Asinϕ  (i) 2ω=Aωcosϕ (ii)

From eq (i) and (ii) 

tanϕ=1 ϕ=45o

Putting value of ϕ in equation (i) 
2=A{12}A=22
 Value of x = 2

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