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A particle executes simple harmonic motion with an amplitude of 5cm .When the particle is at 4cm from the mean position , the magnitude of its velocity in SI units is equal to that of its acceleration . Then its time period in seconds is :

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$\frac{4 π}{3}$

$\frac{3}{8} π$

$\frac{8 π}{3}$

$\frac{7}{3} π$

answer is C.

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Detailed Solution

$w \sqrt{A^{2} - y^{2}} = ω^{2} y$

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