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Q.

A particle executing a simple harmonic motion has a period of 6s. The time taken by the particle to move from the mean position to half the amplitude, starting from the mean position is

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answer is 0.5.

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Detailed Solution

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$y = Asin (\frac{2 π}{T}) t \frac{A}{2} = Asin (\frac{2 π}{T}) t = \frac{2 π}{T} t = π / 6 Time period t = \frac{T}{12} = \frac{6}{12} = \frac{1}{2} s = 0 .5 s$

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A particle executing a simple harmonic motion has a period of 6s. The time taken by the particle to move from the mean position to half the amplitude, starting from the mean position is