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A particle experiences a constant acceleration for 30 sec after starting from rest. If it travels a distance $s_{1}$ in 10 sec and distance $s_{2}$ in the next 20 sec, then

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$s_{1} = \frac{s_{2}}{4}$

$s_{1} = \frac{s_{2}}{2}$

$s_{1} = \frac{s_{2}}{8}$

$s_{1} = s_{2}$

answer is B.

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Detailed Solution

$s_{1} = \frac{1}{2} a {(10)}^{2}$

And $s = \frac{1}{2} a {(30)}^{2} = 9 s_{1}$

$∴ s_{2} = s - s_{1} = 8 s_{1}$

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