A particle goes in a circle of radius 2.0 cm. A concave circle mirror of focal length 20 cm is placed with its principal axis passing through the centre of the circle and perpendicular to its plane. The distance between the pole of the mirror and the centre of the circle is 30 cm the radius of the circle formed by the image is

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8 cm

10 cm

4 cm

6 cm

answer is A.

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Detailed Solution

$f = - 20 cm, u = - 30 cm$

$\begin{array}{l} \frac{1}{v} = \frac{- 1}{20} + \frac{1}{30} \\ v = - 60 cm \end{array}$
Radius of image $= 2 \times object cm$

$= 4 cm$

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