A particle has initial velocity (2i^+3j^) and acceleration (0.3i^+0.2j^). The magnitude of velocity after 10 seconds will be

v→ = u→ +at→= (2i^+3j^) +(0.3i^+0.2j^)×10= 5i^+5j^ ⇒ |v|→= 52 units

A particle has initial velocity (2i^+3j^) and acceleration (0.3i^+0.2j^). The magnitude of velocity after 10 seconds will be

v→ = u→ +at→= (2i^+3j^) +(0.3i^+0.2j^)×10= 5i^+5j^ ⇒ |v|→= 52 units

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A particle has initial velocity $(2 \hat{i} + 3 \hat{j})$ and acceleration $(0 .3 \hat{i} + 0 .2 \hat{j})$ . The magnitude of velocity after 10 seconds will be

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9 units

$9 \sqrt{2} units$

$5 \sqrt{2} units$

5 units

answer is C.

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Detailed Solution

$\vec{v} = \vec{u} + \vec{at}$

= $(2 \hat{i} + 3 \hat{j}) + (0 .3 \hat{i} + 0 .2 \hat{j}) \times 10$

= $(5 \hat{i} + 5 \hat{j}) \Rightarrow | \vec{v |} = 5 \sqrt{2} units$

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A particle has initial velocity (2i^+3j^) and acceleration (0.3i^+0.2j^). The magnitude of velocity after 10 seconds will be

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A particle has initial velocity $(2 \hat{i} + 3 \hat{j})$ and acceleration $(0 .3 \hat{i} + 0 .2 \hat{j})$ . The magnitude of velocity after 10 seconds will be