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Q.

A particle has same range for two angle of projection with same speed 10 ms-1. The corresponding maximum height attained by particle is H1 and H2, respectively. Then, H1 + H2 is

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a

10m

b

12m

c

1m

d

5m

answer is B.

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Detailed Solution

α1+α2=90∘

H1=u2sin2⁡α12g and H2=u2sin2⁡α22g     =u2sin2⁡90∘−α12g=u2cos2⁡α12g∴sin2⁡α1+cos2⁡α1=2gH1u2+2gH2u2∴u2=2gH1+H2∴H1+H2=u22g=10×102×10=5m

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