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Q.

A particle having a charge of q=8.85 μC is placed on the axis of a circular ring of radius R=30 cm at a point P at a distance of a=40 cm from center of ring. Calculate the electric flux passing through the ring (in kNC-1)

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answer is 1000.

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Detailed Solution

The flux is given by

ϕE=q2ε01-aR2+a2 ϕE=8.85×10-628.85×10-121-4050 ϕE=10621-45 ϕE=1062×15=105NC-1 ϕE=100kNC-1

Therefore the flux is 1000kNC-1

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