Q.

A particle having a charge q=1C  and mass m=0.5kg is projected on a rough horizontal plane (x,y)  from a point  (15m,0,0) with a initial velocity  v=20j^ m/s.  In space a uniform electric field  E=25(k^) V/m and magnetic field B=10(k^) T . The acceleration due to gravity  g=10m /sec2 and co–efficient of friction  μ=0.5. The particle moves on a spiral path and stops. Total time of journey is y3sec. Find  y

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answer is 2.

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Detailed Solution

mdvdt=μ(mg+qE)

mv2r=qvBv=qBmr

Differentiating wrt time,

dvdt=qBm×drdt

0tdt=1μa0qBmg+qEdrt=23sec

here initial radius is  a=mvqB=0.5×201×10=1m

Alternate:

mdvdt=μ(mg+qE)

u0dv=μ(mg+qE)m0tdt

t=23s

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